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Find the value of 9m/3^-2=9^-4

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Answer:


m=3^(-12)

Explanation:

we are given that


(9m)/(3^(-2))=9^(-4)


(3^(2)* m)/(3^(-2))=(3^(2))^(-4)

applying the rule of exponents


(m^(a))^(b)=m^(ab)


{3^(2)* m=3^(-8) * 3^(-2)


m=(3^(-8) * 3^(-2))/(3^(2))

applying the rule of exponents


(1)/(m^a)=m^(-a)


m=3^(-8) * 3^(-2)* 3^(-2)


m=3^(-8-2-2)


m=3^(-12)


m=(1)/(3^(12))

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