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Find the area of an equilateral triangle (regular 3-gon) with the given measurement of 6 inch side

User Porgo
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\bf \textit{area of an equilateral triangle}\\\\ A=\cfrac{s^2√(3)}{4}~~ \begin{cases} s=length~of\\ \qquad a~side\\[-0.5em] \hrulefill\\ s=6 \end{cases}\implies A=\cfrac{6^2√(3)}{4}\implies A=9√(3)

User StackHola
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