Question

The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?

Answer 1

Q = 675 [J]

Step-by-step explanation:

We can calculate the amount of heat transfer by means of the following expression that includes the mass and temperature change in a body as a function of the specific heat.

`Q=m*C_(p)*(T_(initial)-T_(final))`

where:

m = mass = 25 [gr]

Cp = specific heat = 0.9 [J/g*°C]

Tinitial = 55 [°C]

Tfinal = 25 [°C]

`Q=25*0.9*(55-25)\\Q=675 [J]`