Answer:
The ratio of lengths of the two mathematical pendulums is 9:4.
Step-by-step explanation:
It is given that,
The ratio of periods of two pendulums is 1.5
Let the lengths be L₁ and L₂.
The time period of a simple pendulum is given by :
![T=2\pi \sqrt{(l)/(g)}](https://img.qammunity.org/2022/formulas/physics/high-school/7mbvhq8ddepgp3nafd5i7273lldl8dtk9s.png)
or
![T^2=4\pi^2(l)/(g)\\\\l=(T^2g)/(4\pi^2)](https://img.qammunity.org/2022/formulas/physics/high-school/hpo8xse7s2g5rpk4pvcway8b2wj344ucww.png)
Where
l is length of the pendulum
![l\propto T^2](https://img.qammunity.org/2022/formulas/physics/high-school/ta07nf2k3k9klh1ui7236lifjl9donrly5.png)
or
....(1)
ATQ,
![(T_1)/(T_2)=1.5](https://img.qammunity.org/2022/formulas/physics/high-school/mzrzjm7cv2g91y5nqe84inw6ddalmfmvrz.png)
Put in equation (1)
![(l_1)/(l_2)=(1.5)^2\\\\=(9)/(4)](https://img.qammunity.org/2022/formulas/physics/high-school/k6m1clkappizrmm31wb6724squf4bawv6v.png)
So, the ratio of lengths of the two mathematical pendulums is 9:4.