Question

Find three consecutive intergers such that three times the third is 102 more than the sum of the first and second.

Answer 1

A) x + x+1 + x+2

We don't need equation A)

B) 3*(x+2) = (x + X+1) +102

3x + 6 = 2x + 1 + 102

x = 97

Numbers are 97, 98 and 99

Explanation: