Question

The final game is altered:

Bag One has 5 red balls and 9 blue balls.
Bag Two has 6 red balls and 7 blue balls.
Complete the tree diagram:

Answer 1

A= 7/13; B=9/14; C= 6/13; D= 63/182; E= 5/14; F= 15/91; G= Red

Explanation:

Answer 2

`\bf A=(7)/(13),B = 9,C=13,D=(63)/(182),E=(5)/(14),F=(15)/(91)\textbf{ and }G=RED`

Explanation:

Number of red balls in bag 1 = 5

Number of blue balls in bag 1 = 9

`\text{So, Probability of drawing red ball = }(5)/(14)\\\\\text{Probability of drawing blue ball = }(9)/(14)`

So, On comparing with the tree diagram :

`B = 9\text{ and }E=(5)/(14)`

Number of red balls in bag 2 = 6

Number of blue balls in bag 2 = 7

`\text{So, Probability of drawing red ball = }(6)/(13)\\\\\text{Probability of drawing blue ball = }(7)/(13)`

`Now, D = (7)/(13)*(9)/(14)=(63)/(182)`

`And, F = (6)/(13)*(5)/(14)=(15)/(91)`

`\bf A=(7)/(13),B = 9,C=13,D=(63)/(182),E=(5)/(14),F=(15)/(91)\textbf{ and }G=RED`