The final game is altered: Bag One has 5 red balls and 9 blue balls. Bag Two has 6 red balls and 7 blue balls. Complete the tree diagram:

Question

asked Feb 10, 2020 215k views

2 Answers

Guichi · Answer 1 · 2020-02-16T13:38:05+0000

Answer:

$\bf A=(7)/(13),B = 9,C=13,D=(63)/(182),E=(5)/(14),F=(15)/(91)\textbf{ and }G=RED$

Explanation:

Number of red balls in bag 1 = 5

Number of blue balls in bag 1 = 9

$\text{So, Probability of drawing red ball = }(5)/(14)\\\\\text{Probability of drawing blue ball = }(9)/(14)$

So, On comparing with the tree diagram :

$B = 9\text{ and }E=(5)/(14)$

Number of red balls in bag 2 = 6

Number of blue balls in bag 2 = 7

$\text{So, Probability of drawing red ball = }(6)/(13)\\\\\text{Probability of drawing blue ball = }(7)/(13)$

Now, D = (7)/(13)*(9)/(14)=(63)/(182)

And, F = (6)/(13)*(5)/(14)=(15)/(91)

$\bf A=(7)/(13),B = 9,C=13,D=(63)/(182),E=(5)/(14),F=(15)/(91)\textbf{ and }G=RED$