As we know that in order to melt the copper we need to take the temperature of copper to its melting point
So here heat required to raise the temperature of copper is given as
![Q = ms\Delta T](https://img.qammunity.org/2020/formulas/physics/middle-school/aaojl4max645uc8q0wgmab8qye2npoievb.png)
We know that
melting temperature of copper = 1085 degree C
Specific heat capacity of copper = 385 J/kg C
now we have
![Q = 3(385)(1085 - 83)](https://img.qammunity.org/2020/formulas/physics/middle-school/dnxh5tv4nrrlfd7s4a5kca9qfe69f78pdu.png)
![Q = 1157310 J](https://img.qammunity.org/2020/formulas/physics/middle-school/r2xs6bu57ij93b362p0eejn7yegwatx5u2.png)
![Q = 1157.3 kJ](https://img.qammunity.org/2020/formulas/physics/middle-school/s5blbwjmhrrgik0b8jid49etjdcvyr1r6n.png)
now in order to melt the copper we know the heat required is
![Q = mL](https://img.qammunity.org/2020/formulas/physics/middle-school/4swgto415889swbdbuaza020yemeslddrt.png)
here we know that
L = 205 kJ/kg
now from above formula
![Q = 3(205) kJ](https://img.qammunity.org/2020/formulas/physics/middle-school/bx32qpv77960sozijtj9uqifazb5wcugya.png)
![Q = 615 kJ](https://img.qammunity.org/2020/formulas/physics/middle-school/lua3larwkcr92yws8xalcepte87ndgzbqu.png)
now total heat required will be
![Q = 1157.3 kJ + 615 kJ](https://img.qammunity.org/2020/formulas/physics/middle-school/5yu2hyxbizdm6yi0b9n0qiftpinjeo3k9q.png)
![Q = 1772.3 kJ](https://img.qammunity.org/2020/formulas/physics/middle-school/108epj8xbyw1subkjdoyi8x8hevs89xefb.png)
As we know that
![1 Cal = 4.18 kJ](https://img.qammunity.org/2020/formulas/physics/middle-school/zl2l54leiojz851iyhcsd3znxzzr7j8299.png)
now we have
![Q = (1772.3)/(4.18) = 430 KCal](https://img.qammunity.org/2020/formulas/physics/middle-school/qaho093cdph1wzbna8ijqurcdqg9gmib8j.png)