Question

What is the value of h when the function is converted to vertex form?

Answer 1

The value of h is 7.

Explanation:

The given function is

`p(x)=x^2-14x+29`

where
`a=1,b=-14,c=29`

The h-value of the vertex can be calculated with the formula;

`h=-(b)/(2a)`

We substitute the necessary values to obtain;

`h=-(-14)/(2(1))`

Simplify to get;

`h=7`

Answer 2

Answer: h=7

Explanation:

By definition the function in vertex form is:

`f(x)=a(x-h)^(2)+k`

Where (h,k) is the vertex of the parabola.

You must group the terms that contain the same variable in the function:

`f(x)=(x^(2)-14x)+29`

Complete the square as following:

`f(x)=(x^(2)-14x+49)+29-49`

Now you must rewrite it as following:

`f(x)=(x-7)^(2)-20`

Then:

h=7