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Determine if the function is an even function, an odd function or neither.

Determine if the function is an even function, an odd function or neither.-example-1
User Matej
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6.0k points

2 Answers

2 votes

Answer:

Choice A is correct.

Explanation:

We have given a function.

y = 2x⁴ +2x²

suppose y = f(x) , we get,

f(x) = 2x⁴ +2x²

We have to find that is this function is even or odd?

A function is even if f(x) = f( -x).

A function is odd if f(x) = - f(x).

Putting x = -x in f(x) we get,

f(-x) = 2(-x)⁴+2(-x)²

f(-x) = 2x⁴+2x²

f(-x) = f(x)

So, the function is even.

User Micnyk
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5.6k points
4 votes

Answer: Option a.

Explanation:

By definition, a functioon is even when:


f(x)=f(-x)

And it is odd when:


-f(x)=f(-x)

Therefore, you can verify if the function is even substituting -x into the function:


f(-x)=2(-x)^(4)+2(-x)^(2)\\f(-x)=2x^(4)+2x^(2)

Then:


-f(x)=f(-x)

It is an even function.

User Jason Lam
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6.0k points