Question

The end of the rain gutter has the shape of a trapezoid with the measurements shown. Find the area of this end.

A.) 40 in squared
B.) 5 square root 17 in squared
C.) 20 in squared
D.) 24 in squared

Answer 1

Area = 1/2 × (Sum of parallel sides) × height

Area = 1/2 × (6+4) × 4 = 10×2 =20in ^2

AREA = 20 in squared

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Answer 2

Answer: C.) 20 in squared

Explanation:

We know that the area of a trapezoid is given by :-

`\text{Area}=(1)/(2)(a+b)h`, where a and b are the lengths of the opposite parallel sides and h is height of the trapezoid.

From the given picture , a = 6 in.

b= 4 in.

h = 4 in.

Then , the area of the trapezoid will be :-

`\text{Area}=(1)/(2)(6+4)4\\\\\Rightarrow\ \text{Area}=\text{ 20 in. squared}`

Hence, the area of this end = 20 in squared