135k views
3 votes
Find the point, M, that divides segment AB into a ratio of 2:3 if A is at (0, 15) and B is at (20, 0).

A. (8, 9)
B. (9, 9)
C. (9, 12)
D. (8, 12)

1 Answer

0 votes

Answer: option A

Step-by-step explanation:

Let,

(x,y) be the coordinate of point M.

Here M divides the line AB in ratio 2:3.

I'll write given information in a standard format so that you can easily apply it in formula:

A(0,15)=A(x1,y1)

B(20,0)=B(x2,y2)

ratio(m1:m2)=2:3

Now we use section formula of internal division to find coordinates of M,

x=(m1 × x2 + m2 × x1)/(m1+m2)

=(2×20+3×0)/(2+3)

=40/5

=8

&,

y=(m1 × y2 + m2 × y1)/(m1+m2)

=(2×0+3×15)/(2+3)

=45/5

=9

Required answer: M(8,9)

User Dan Hennion
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories