Question

What is the perimeter of quadrilateral ABCD? a(-3,2) b(4,2) c(3,-3) d(-3,3)

Answer 1

Perimeter of ABCD = 21.58 units

Explanation:

Distance formula:-

Le (x₁,y₁) and (x₂,y₂) be the two end points of a line segments.Then length of segment = √[(x₂ - x₁)² + (y₂ - y₁)²]

It is given that,

ABCD is a quadrilateral A(-3,2) B(4,2) C(3,-3) D(-3,3)

To find the side length of quadrilateral

A(-3,2) , B(4,2), C(3,-3) and D(-3,3)

AB = √[(4 --3)² + (2 - 2)²] = √[(4 +3)² + 0] = 7

B(4,2) C(3,-3)

BC = √[(3 - 4)² + (-3 - 2)²] = √26 = 5.1

CD = √[(-3 - 3)² + (3 - -3)²] =√72 = 8.48

AD = √[(-3 - -3)² + (3 - 2)²] =1

To find perimeter of ABCD

Perimeter = AB + BC + CD + AD = 7 + 5.1 + 8.48 + 1= 21.58

Answer 2

Perimeter will be = 21.6

Explanation:

As we know the formula to get the length between two points A and B having coordinates A(x,y) and B (a,b) is

AB = √(x-a)²+(y-b)²

We will use this formula to get the lengths of all sides of the quadrilateral.

AB=√(4+3)²+(2-2)² =√7² =7

BC = √(3-4)²+(-3-2)²=√(-1)²+(-5)² = √1+25=√26 = 5.1

CD = √(3+3)²+(-3-3)² = √6²+(-6)² = √72 = 8.5

DA = √(-3+3)²+(3-2)² =√1 = 1

Since perimeter of the quadrilateral = sum of lengths of all sides

Perimeter = 7 + 5.1 + 8.5 + 1 = 21.6