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Write an equation for the line that passes through (4,-6) and (-7,-6). Is the line parallel or perpendicular to the y-axis?

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Answer:

y = -6, perpendicular

Explanation:

You can use the points to find the slope of the line:


m=(y_(2)-y_(1))/(x_(2)-x_(1)) =(-6-(-6))/(-7-4) =(-6+6)/(-7-4)=(0)/(-11)=0

Then, using point-slope form, choose one set of coordinates to use for y1 and x1:


y-y_(1)=m(x-x_(1))


y-(-6)=0(x-4)


y+6=0


y=-6

Since the slope of the line is zero, it's a horizontal line. The y-axis is a vertical line, which means that the line is perpendicular to the y-axis.

User Venkat Prasanna
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