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Find an equation of the line parallel to x=5y-9 and passing through (2,-4). Express in standard form.

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Answer:

x - 5y = 22

Explanation:

Step 1: rewrite the equation of the given line in to slope-intercept form by solving for y

x = 5y - 9

-5y = -x - 9 (subtract 5y and x from both sides)

y = x/5 + 9/5 (divide both side by -5)

Step 2: Our line is parallel to this line, so it has the same slope, but a different y-intercept, so set up the equation...

y = x/5 + b

We are given a point (x, y) of (2, -4), so plug that in and solve for b.

-4 = 2/5 + b

-4 - 2/5 = b (subtract 2/5 from both sides to isolate b)

-20/5 - 2/5 = b

-22/5 = b (simplify)

So the equation of our line is y = x/5 - 22/5

Step 3: Standard form is ax + by = c, where a is a positive integer

subtract x/5 from both sides...

-x/5 + y = - 22/5

multiply by -5 so x becomes a positive integer

x - 5y = 22

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