Answer:
Part A) The inequality that represent this situation is equal to
![p\leq \$450](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wr2hnrg8voj5n4hnstfe2hmqo802rl2xco.png)
Part B) Computer A, Computer B,
Explanation:
Part A)
Let
p------> the price of a new laptop computer
we know that
The inequality that represent this situation is equal to
![p\leq \$450](https://img.qammunity.org/2020/formulas/mathematics/middle-school/wr2hnrg8voj5n4hnstfe2hmqo802rl2xco.png)
Part B)
we know that
If a price is a solution of the inequality, then the price must satisfy the inequality
Verify each case
case A) For
![p=\$419](https://img.qammunity.org/2020/formulas/mathematics/middle-school/4c0bmydsaeue5qit7xvazsewqf2dx4qn20.png)
Substitute the value of p in the inequality and then compare
------> is true
therefore
Rebecca can buy computer A
case B) For
![p=\$450](https://img.qammunity.org/2020/formulas/mathematics/middle-school/e8uwql6lma55w5p733t0iufaa2lifn8t0c.png)
Substitute the value of p in the inequality and then compare
------> is true
therefore
Rebecca can buy computer B
case C) For
![p=\$468](https://img.qammunity.org/2020/formulas/mathematics/middle-school/suao6rkpt4ge5rtlhv6bvlijawxc7v94fs.png)
Substitute the value of p in the inequality and then compare
------> is not true
therefore
Rebecca cannot buy computer C
case D) For
![p=\$451](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rnc4s9tahrym0rdfb41l2471p3pn7xyzpg.png)
Substitute the value of p in the inequality and then compare
------> is not true
therefore
Rebecca cannot buy computer D