Answer:
Option A
Explanation:
We assume that after the first player and second player choose a card they do not return the card to the deck and that the events are mutually exclusive (ie, you can not get a queen and jack by selecting a single card).
It can be seen in the figure that there are 52 cards in the deck. It can be seen that there are 4 queens and 4 jacks.
Thus:
If the first player selected a jack, then there are only 3 jacks left in the deck, and 51 cards in total.
If the second player selected a queen, then there are only 3 queens left in the deck and 50 cards in total.
Therefore, the probability Pj that the third player selects a Jack
is
![P_(j) = (3)/(50)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/6t37705lwbnrrrwlsu3f1sc4tyxep4ckix.png)
Then, the probability Pq that the third player selects a queen
is
![P_(q) = (3)/(50)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/15aobpyfq63gmqjmmf431dl5haymj0s1n1.png)
Finally the probability of selecting a jack or queen is:
P(j ∪ q) =
![P_(j) + P_(q)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ciu3bxjuf0l31epn2nca5yy5onpa2hxidf.png)
P(j ∪ q) =
![(3)/(50) + (3)/(50)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/rfpn219oxqy7klzqxakm8j6u909lrc5krf.png)
P(j ∪ q) =
.
The correct answer is the first option.