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The score of Sachin in consecutive five innings at 80, 90 ,100, 100 and M respectively. the average of the five inning is 100 , then comparing with his first inning scored , how much more has scored in his last innings ?

​the answer is 50 but how....

User Hector
by
8.4k points

1 Answer

10 votes

Step-by-step explanation:

The score of Sachin in consecutive five innings at 80, 90 ,100, 100 and M respectively.

The average of the five innings is 100.

We need to find the value of M.

Average = sum of observations/total no of observations

Sum of observations = 80+90+100+100+M

= 370 + M

Total no. of observations = 5

Put all the values,


100=(370+M)/(5)\\\\500=370+M\\\\M=500-370\\\\M=130

So, he scored 130 in his last innings.

He scored (130-80 = 50) more in his last innings as compared to the first inning scored.

User ChrisCantrell
by
8.7k points
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