Answer:
As below
Explanation:
using eq from problem 4) y = -45x + 1080
then use the point slope formula with the slope of the above line at -45 and plug in your given point of (8, 240)
y-y1 = m(x-x1) where m is the slope above
y-240 = -45 (x - 8 ) this is an equation for the line but the teacher probably wants the slope intercept form... the formula is y = mx + b
soooo...
y-240 = -45x + 360
y = -45x +360 + 280
y = -45x + 640
there you go :)