220k views
3 votes
find the minimum value of p=10x+26y the constraints are x+y less than or equal to 6, 5x+y greater than or equal to 10, x+5y greater than or equal to 14

1 Answer

3 votes

Answer:

Minimum value of
p=10x+26y is 80 at (1.5,2.5)

Explanation:

We are given

The objective function is, Minimize
p=10x+26y

With the constraints as,


x+y\leq 6\\5x+y\geq 10\\x+5y\geq 14

So, upon plotting the constraints, we see that,

The boundary points of the solution region are,

(1,5), (1.5,2.5) and (4,2).

So, the minimum values at these points are,

Points
p=10x+26y

(1,5)
p=10x* 1+26* 5 i.e. p = 140

(1.5,2.5)
p=10* 1.5+26* 2.5 i.e. p= 80

(4,2)
p=10* 4+26* 2 i.e. p = 92

Thus, the minimum value of
p=10x+26y is 80 at (1.5,2.5).

find the minimum value of p=10x+26y the constraints are x+y less than or equal to-example-1
User Hadvig
by
6.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.