Question

Find the value of b and c

PLEASE SHOW WORK!

b(3x
`x^(2)`-2x+c) = 9
`x^(2)` - 6x+15

Answer 1

b=3

c=5

Explanation:

b(3x^{2}-2x+c) = 9x^{2} - 6x+15

Distribute

3b x^2 -6x +bc = 9x^2 -6x +15

Each term must be equal

3bx^2 = 9x^2

3b = 9

Divide by 3

3b/3 = 9/3

b =3

bc = 15

3c =15

Divide by 3

3c/3 = 15/3

c =5