Question

What is the vertex of -3x^2+6x+17 ?

Answer 1

(1, 20)

Explanation:

Given the quadratic function: -3x² + 6x + 17, this is the general form of the function ax² + bx + c. So, for the given function:

a = -3

b = 6

c = 17

The vertex can be found by solving for 'h' and 'k' using the following formulas:

h =
`(-b)/(2a)=(-6)/((22*-3))=(-6)/(-6)=1\\`

k =
`c-(b^(2) )/(4a)=17-(6^(2) )/(4(-3))=17-(36)/(-12)=17+3=20`