Question

A rescue plane is flying horizontally at a height of 132 m above the ground. The pilot spots a survivor and releases an emergency kit with a parachute. The kit descends at a constant vertical acceleration of and the initial plane horizontal speed is . Assuming air resistance and wind are negligible, how far away from the survivor will the emergency kit hit the ground?

446 m

301 m

2.64 km

426 m

Answer 1

Answer;

= 426 m

Explanation;

Time taken to reach Earth = t

s = ut + ½at²

Vertically initial velocity = u = 0

Therefore;

132 = 0t + ½6.89t²

=132/3.445 = t²

= 38.316 = t²

t = 6.19 s

Range = horizontal distance = speed x time

= 68.9 x 6.19

≈ 426 m

Hence the emergency kit impacts the ground 426 m from the survivor