Question

A sample of oxygen gas occupies 3.60 liters at a pressure of 1.00 atm. If temperature is held constant, what will be the volume of the oxygen gas at a pressure of 2.50 atm?

0.694 L

1.44 L

4.35 L

9.20 L

Answer 1

P1V1=P2V2
(1.00atm)(3.60L)=(2.50atm)V
3.60=(2.50atm)V
3.60/2.50=V
1.44L=V

Answer 2

The volume of O2 gas = 1.44 L

Step-by-step explanation:

Given:

Initial volume of O2 gas, V1 = 3.60 L

Initial pressure, P1 = 1.00 atm

Final pressure, P2 = 2.50 atm

To determine:

Final volume of O2 gas, V2

Step-by-step explanation:

Based on the ideal gas equation

`PV = nRT\\`

where n = moles of gas

R = gas constant, T = temperature

At constant T, the above equation becomes:

PV = constant

`i.e.\ P1V1= P2V2\\\\V2 = (P1V1)/(P2) = (1.00atm*3.60 L)/(2.50atm) =1.44\ L`