Question

Molecular iodine, i2(g), dissociates into iodine atoms at 625 k with a first-order rate constant of 0.271 s−1. part a part complete what is the half-life for this reaction?

Answer 1

2.775 s.

Step-by-step explanation:

The half-life time for a first order reaction = 0.693 / k.

Where, k is the rate constant of the reaction.

∴ The half-life time = 0.693 / k = (0.693) / (0.271 s⁻¹) = 2.775 s.