63.8k views
2 votes
I need it step by step please​

I need it step by step please​-example-1

2 Answers

8 votes
2y+4x=12

Move 4x to the other side as a negative number

2y=-4x+12

Divide all terms by 2

y=-2x+6

Now, in order for two lines to be perpendicular, their gradients have to multiply obeyed to get -1 (let a be the gradient of the given line and let b be the gradient of the line we're trying to find)

So, we do -2*b=-1

so, b is equal to 1/2

Now, we are given a coordinate so we substitute it in y-y1=m(x-x1)

y-1=1/2(x-8)

Expand brackets

y-1= 1/2x-4

Take -1 to the other side as a positive number

y=1/2x-3

So, the equation of the line is y=1/2x-3


User Ranjeet
by
7.8k points
6 votes

Answer:

1/2x-3

Explanation:

First, make the equation 2y+4x=12 into a linear equation(y=mx+b)

2y=-4x+12

y=-2x+6

From this, you know the slope is -2.

The perpendicular of any slope is going to be the negative inverse.

negative inverse: a/b-->-b/a

so basically flip it and make it negative(make it positive if the original is negative).

So, for -2 it would be 1/2

Now right the equation for the perpendicular line.

y=1/2x+b

b is the y intercept, and since you want to make the line go through (8,1) you have to change the 6 in the original equation.

To do this replace x and y with 8 and 1

1=1/2(8)+b

1=4+b

b=-3

So you plug that into the equation

y=1/2x-3

I need it step by step please​-example-1
User Mmirzadeh
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories