Answer:
B and C are both applicable in this case.
Explanation:
The terminal point determined by theta can not be in quadrant 3 since tan theta is greater than zero in this quadrant. In addition, if tan theta =-12/5 then csc theta = ±13/12 since the terminal point determined by theta can be in quadrant 2 where sine theta and consequently csc theta would be positive or in quadrant 4 where csc theta would be negative.