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Given that p varies directly as the square of q and p equal 12 when q equal 3 find the value of p when q equal 5

User Seif Sayed
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1 Answer

2 votes

Answer:

p = 100/3

Explanation:

P varies directly as q^2 and

p = k q^2

We know p =12 and q =3, we can solve for k

12 = k 3^2

12 = k*9

Divide by 9

12/9 =k

4/3 = k

p = 4/3 q^2

When q = 5

p = 4/3 * 5^2

p = 4/3*25

p = 100/3

User Dimitris Damilos
by
8.2k points

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