Answer:
4x^2 +84x+440
840 in^2
Explanation:
The length of the picture and frame is x+ 22+x= 2x+22
The width of the picture and frame is x +20+x = 2x+20
Area is length times width
A = (2x+22) *(2x+20)
We can FOIL to find the area
first 2x*2x = 4x^2
outer 2x*20 =40x
inner 2x*22 = 44x
last = 22*20 = 440
Add these together
4x^2 +40x+44x+440
4x^2 +84x+440
b. x=4
4x^2 +84x+440
4(4)^2 +84(4) +440
4*16 +336+440
64+776
840