Answer: The potential difference from the sphere's surface to its center is zero.
Step-by-step explanation:
The expression for the potential difference due to charge is as follows;

Here,
is the potential difference, q is the charge, r is the position and
is the absolute permittivity of free space.
In the given problem, a solid sphere of radius r carries charge q distributed uniformly throughout its volume.
To find the potential difference from the sphere's surface to its center. Put r=0 in the expression of the potential difference.


Therefore, the potential difference from the sphere's surface to its center is zero.