A solid sphere of radius r carries charge q distributed uniformly throughout its volume. find the potential difference from the sphere's surface to its center.

Question

asked Aug 3, 2020 42.4k views

1 Answer

Polmarex · Answer 1 · 2020-08-09T19:59:42+0000

Answer: The potential difference from the sphere's surface to its center is zero.

Step-by-step explanation:

The expression for the potential difference due to charge is as follows;

$\Delta V=(q)/(4\pi \epsilon _(0)r)$

Here,
$\Delta V$ is the potential difference, q is the charge, r is the position and
$\epsilon _(0)}$ is the absolute permittivity of free space.

In the given problem, a solid sphere of radius r carries charge q distributed uniformly throughout its volume.

To find the potential difference from the sphere's surface to its center. Put r=0 in the expression of the potential difference.

$\Delta V=(q)/(4\pi \epsilon _(0)(0))$

$\Delta V=0$

Therefore, the potential difference from the sphere's surface to its center is zero.