Question

Prove that 2017(2018^9+2018^8+…+2018^2+2019+1)=2018^10+2017

Answer 1

2016

Explanation:

Answer 2

let a=2018, we can rewrite the question into


`(a-1)(a^9+a^8+...+a^2+a+2)\\=(a-1)(a^9+a^8+...+a^2+a+1)+(a-1)\\=a^(10)-1+a-1`

substitute back a = 2018, obtained


`{2018}^(10) + 2016`
well, there is something wrong here