Question

I need help showing the work. please help

Answer 1

see explanation

Explanation:

Using the laws of logarithms

• log x + log y ⇔ log(xy)

• log x - log y ⇔ log (
`(x)/(y)`)

• log
`x^(n)` ⇔ nlog x

Hence

2
`log_(3)` x +
`log_(3)` 2x -
`log_(3)`(x - 3)

=
`log_(3)` x² +
`log_(3)` 2x -
`log_(3)`(x - 3)

=
`log_(3)` 2x³ -
`log_(3)`(x - 3)

=
`log_(3)`(
`(2x^3)/(x-3)`)