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Question 1. In the following equation for the alpha decay of bismuth-214, supply the missing element that correctly completes the equation.

Question 2. Complete the following equations by correctly matching the appropriate product.

Question 1. In the following equation for the alpha decay of bismuth-214, supply the-example-1
Question 1. In the following equation for the alpha decay of bismuth-214, supply the-example-1
Question 1. In the following equation for the alpha decay of bismuth-214, supply the-example-2

2 Answers

5 votes
Q1. TI (210/81Thallium)
Q2.
The answers are opposite from each other

User Greg Najda
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Answer: a) Tl (Thallium)

b)
^(210)_(84)\textrm{Bi}\rightarrow ^(206)_(82)\textrm{Pb}+^4_2\textrm{He}


^(218)_(84)\textrm{Bi}\rightarrow ^(214)_(82)\textrm{Pb}+^4_2\textrm{He}


^(214)_(84)\textrm{Bi}\rightarrow ^(210)_(82)\textrm{X}+^4_2\textrm{He}

Step-by-step explanation:

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

General representation of an element is given as:
_Z^A\textrm{X}

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Total mass on reactant side = total mass on product side

214= A + 4 , A = 210

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

83= Z + 2, Z = 81


^(214)_(83)\textrm{Bi}\rightarrow ^(A)_(Z)\textrm{X}+^4_2\textrm{He}

b)

1.
^(210)_(84)\textrm{Bi}\rightarrow ^(206)_(82)\textrm{Pb}+^4_2\textrm{He}

Total mass on reactant side = total mass on product side

210= A + 4 , A = 206

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

84= Z + 2, Z = 82

2.
^(218)_(84)\textrm{Bi}\rightarrow ^(214)_(82)\textrm{Pb}+^4_2\textrm{He}

Total mass on reactant side = total mass on product side

218= A + 4 , A = 214

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

84= Z + 2, Z = 82

3.
^(214)_(84)\textrm{Bi}\rightarrow ^(210)_(82)\textrm{X}+^4_2\textrm{He}

Total mass on reactant side = total mass on product side

214= A + 4 , A = 210

To calculate Z:

Total atomic number on reactant side = total atomic number on product side

84= Z + 2, Z = 82

User David Blaney
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