Result:
![\boldsymbol{20}](https://img.qammunity.org/2023/formulas/mathematics/high-school/te8vhdnvtguqgxn4g1rvbu67y5y443l6o9.png)
The result is rational because it can be written as the ratio of two integers and its decimal expansion does terminate or repeat.
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Step-by-step explanation:
Let's simplify the expression to get...
![2√(16)+4√(9)\\\\2√(4^2)+4√(3^2)\\\\2*4+4*3\\\\8+12\\\\20\\\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/c30fvyshem4187haz20q4eeqqghtt7gff9.png)
Therefore,
![2√(16)+4√(9)=20\\\\](https://img.qammunity.org/2023/formulas/mathematics/high-school/yozctxzhq9r0gneog4w5pgl7kznheuq2r1.png)
Since
, we have a rational number here. It's a fraction of two integers
![\text{rational number} = \frac{\text{integer}}{\text{integer}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/kmfkad9ljds6mczjmokjuxw5isqw4adulu.png)
We cannot have zero in the denominator.
One property of rational numbers is that the decimal expansion either terminates or it repeats (one option only).
In this case, we have a terminating decimal because 20 = 20.0; ie the decimal doesn't go on forever.
In contrast, something like 1/3 = 0.33333... has the '3's go on forever to be a repeating decimal.