Question

What is the midpoint of the line segment with endpoints of (-2,-2) and (4,6)?

A) (1,4)
B) (2,4)
C) ( 2,2)
D) (1,2)

Answer 1

Choice D is correct answer.

Explanation:

We have given end-points of a line segment.

We have to find Mid-point of line segement.

(x₁,y₁) = (-2,-2) and (x₂,y₂) = (4,6)

M = ?

The formula to find Mid-point is:

M = (x₁+x₂/2, y₁+y₂/2)

Putting given values in above, formula, we have

M = (-2+4/2,-2+6/2)

M = (2/2,4/2)

M = (1,2) is mid-point of the line segment with end-points of (-2,-2) and (4,6).

Answer 2

option (d) is correct.

The mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Explanation:

Given: end points of a line segment as (-2,-2) and (4,6)

We have to find the mid points of the line segment whose ends points are given.

Mid point formula is stated as ,

For a line having end points as
`\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right)` , the mid point can be calculated as,

`\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left((x_2+x_1)/(2),\:\:(y_2+y_1)/(2)\right)`

Here,

`\left(x_1,\:y_1\right)=\left(-2,\:-2\right),\:\left(x_2,\:y_2\right)=\left(4,\:6\right)`

Substitute in mid point formula, we get,

`=\left((4-2)/(2),\:(6-2)/(2)\right)`

Solving further , we get,

`=\left(1,\:2\right)`

Thus, the mid points of the line segment whose ends points are (-2,-2) and (4,6) is (1,2)

Thus, option (d) is correct.