Question

Find the difference.

(4x3−12x2−5)−(−8x2+4x+3)=

Answer 1

4x³-4x²-4x-8

Explanation:

We have given an expression.

(4x³-12x²-5) - (-8x²+4x+3)

We have to simplify above expression.

Open parentheses and distribute negative sign on second parentheses.

4x³-12x²-5+8x²-4x-3

Collect like terms

4x³-12x²+8x²-4x-5-3

Add the coefficients of x² and constant

4x³+(-12+8)x²-4x+(-5-3)

Simplify

4x³+(-4)x²-4x+(-8)

4x³-4x²-4x-8 which is the answer.

Answer 2

4x³ - 4x² - 4x -8

Explanation:

It is given that,

4x³ - 12x² - 5 -(-8x² + 4x + 3) -----(1)

This expression shows the subtraction of two algebraic expression.

Let eq(1) 4x³ - 12x² - 5 -(-8x² + 4x + 3)

⇒4x³ - 12x² - 5 +8x² - 4x - 3 (open bracket)

= 4x³ - 12x² + 8x² - 4x -5 -3 (write similar terms together)

= 4x³ - 4x² - 4x -8

Therefore the difference of 4x³ - 12x² - 5 -(-8x² + 4x + 3) is given by,

4x³ - 4x² - 4x -8