As we know that the velocity at any instant is defined as slope of displacement time graph at that instant
so we will have
![v = (ds)/(dt)](https://img.qammunity.org/2020/formulas/physics/middle-school/v0ofiicf0354km178zpcag08t8k2w123uh.png)
now we will say
slope of the graph is also defined as
![slope = tan\theta](https://img.qammunity.org/2020/formulas/physics/middle-school/opu2pypyygcbw7i50yu745vt8m8y5znevo.png)
now on increasing the value of the slope we will have more steep graph
so more steep graph will have more value of theta
so for steep graph
![\theta = large](https://img.qammunity.org/2020/formulas/physics/middle-school/mtiv1p5fq6im8gzhuk245bm8ugfwgfa143.png)
![tan\theta = large](https://img.qammunity.org/2020/formulas/physics/middle-school/v79mxvt7x8gztuqdh86aqnzrydun8eggvn.png)
so value of the velocity will be large at steep graph