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write the first four terms of the function f(n)=n^2-1

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Answer:

0,3,8,15

Explanation:

f(n)=n^2-1

The first term is

f(1) = 1^2 -1 = 1-1 =0

The second terms is

f(2) = 2^2 -1 = 4-1 = 3

The third term is

f(3) = 3^2 -1 = 9-1 =8

The fourth term is

f(4) = 4^2 -1 = 16-1 =15

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