Question

a photographer shines a camera light at a particular painting forming an angle of 50 degrees with a camera platform at the light is 55 feet from the wall where the painting hangs how high above the platform is the painting​

Answer 1

The painting is 42.13 feet above the platform

Explanation:

Refer the attached figure .

A particular painting forming an angle of 50 degrees with a camera platform .

∠ABC = 50°

We are also given that the light is 55 feet from the wall where the painting hangs

i.e. AB = 55 feet.

Now we are required to find how high above the platform is the painting​. i.e. AC

So, we will use trigonometric ratio :

`sin\theta = (Perpendicular)/(Hypotenuse)`

`sin50^(circ) = (AC)/(AB)`

`sin50^(circ) = (AC)/(55)`

`0.766*55 = AC`

`42.13= AC`

Thus the painting is 42.13 feet above the platform