132k views
2 votes
Write the equation in general form of a line with a slope of -1/3 and y intercept of 10/3

10x+3y-1=0
x+3y+10=0
x+3y-10=0
10x-3y-1=0

User Vasilisa
by
8.2k points

1 Answer

5 votes

Answer:


x + 3y -10 = 0

Explanation:

Begin by writing the equation of the line in slope intercept form, y=mx+b.

Substitute m= -1/3 and b = 10/3.


y = -(1)/(3)x + (10)/(3)

Convert to general from by moving both -1/3x and 10/3 to the other side of the equal sign. Then multiply the entire equation by 3 to clear the fractions.


(1)/(3)x + y - (10)/(3) = 0\\\\3((1)/(3)x + y - (10)/(3) = 0)\\\\x + 3y -10 = 0

User Pflevy
by
9.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories