Question

Write the equation in general form of a line with a slope of -1/3 and y intercept of 10/3

10x+3y-1=0
x+3y+10=0
x+3y-10=0
10x-3y-1=0

Answer 1

`x + 3y -10 = 0`

Explanation:

Begin by writing the equation of the line in slope intercept form, y=mx+b.

Substitute m= -1/3 and b = 10/3.

`y = -(1)/(3)x + (10)/(3)`

Convert to general from by moving both -1/3x and 10/3 to the other side of the equal sign. Then multiply the entire equation by 3 to clear the fractions.

`(1)/(3)x + y - (10)/(3) = 0\\\\3((1)/(3)x + y - (10)/(3) = 0)\\\\x + 3y -10 = 0`