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Find the perimeter of a regular heptagon with consecutive vertices at "A" (-2,-5) and "B" (1,-9)

User Halloei
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1 Answer

6 votes

Answer:

Perimeter is 35 units.

Explanation:

A heptagon has 7 equal sides.

Given the length of two consecutive vertices, A(-2-5) and B(1,-9).

We can find the length of AB and multiply by 7.

Recall the distance formula;


d=√((x_2-x_1)^2+(y_2-y_1)^2)

The length of AB is


|AB|=√((-2-1)^2+(-5--9)^2)


|AB|=√((-3)^2+(4)^2)


\Rightarrow |AB|=√(9+16)


\Rightarrow |AB|=√(25)


\Rightarrow |AB|=5\:units

Therefore the perimeter is
7* 5=35\:units.

User Alan Rowarth
by
8.3k points

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