Answer: a) probability that the game will be canceled= 45%
b) probability there will be a light drizzle and the game will not be canceled=20%
Explanation:
Since we have given that
Probability of heavy fog is given by

Probability of a light drizzle is given by

Probability of getting canceled a softball game due to light drizzle is given by

Probability of getting canceled a softball game due to heavy fog is given by

a. Find the probability that the game will be canceled.
Probability of getting the game be cancelled is given by

b. Find the probability there will be a light drizzle and the game will not be canceled.
Probability that there will be a light drizzle and the game will not be canceled is given by

Hence, a) probability that the game will be canceled= 45%
b) probability there will be a light drizzle and the game will not be canceled=20%