Question

Find an equation of a line with slope -3/4 and that passes through P(-4,6) in standard, form.

Answer 1

`y = - (3)/(4)x + 3`

Explanation:

the standard form of any straight line is:

y = m × x + c

where: y is the y value of the point

x is the x value of the point

m is the gradient/slope

SOLUTION

`y = mx + c \\ 6 = - (3)/(4) ( - 4) + c \\ c = 3`