Question

Use the information given in the graph to write the standard form of the parabola.

x2 = –16y
y2 = –16x
x2 = –4y
y2 = –4x

Answer 1

B

Explanation:

edge 2021

Answer 2

`y^(2)=-16x`

Explanation:

we know that

The equation of a horizontal parabola written in standard form is equal to

`(y-k)^(2)=4p(x-h)`

where

(h,k) is the vertex of the parabola

In this problem we have

`(h,k)=(0,0)`

The coordinates of the focus are (h+p,k)

In this problem we have

`F(-4,0)`

therefore

`p=-4`

substitute

`(y-0)^(2)=4(-4)(x-0)`

`y^(2)=-16x`