Question

Solve for x in the equation x² + 2x + 1 = 17.

Answer 1

option A). x = [-1 ± √15] is the correct answer

Explanation:

Formula:-

for a quadratic equation ax² + bx + 0 = 0

x = [-b ± √(b² - 4ac)]/2a

To find x

Here quadratic equation be, x² + 2x + 1 = 17

⇒ x² + 2x + 1 - 17 = 0

⇒ x² + 2x - 16 = 0

a = 1, b = 2 and c -16

x = [-b ± √(b² - 4ac)]/2a

x = [-2 ± √(2² - 4*1*(-16))]/2*1

x = [-2 ± √(4 -64)]/2

x = [-2 ± √(60)]/2

x = [-2 ± 2√15]/2

x = [-1 ± √15]

Therefore option A). x = [-1 ± √15] is the correct answer

Answer 2

Answer: Second option.

Explanation:

1. To solve this problem you can applly the quadratic formula, which is shown below:

`x=\frac{-b+/-\sqrt{b^(2)-4ac}}{2a}`

2. The quadratic equation is:

`x^(2)+2x+1-17=0\\x^(2)+2x-16=0`

3. Then:

a=1

b=2

c=-16

4. Therefore, when you substitute these values into the quadratic formula, you obtain the following result:

`x=\frac{-2+/-\sqrt{(2)^(2)-4(1)(-16)}}{2(1)}`

x=-1±√17