Question

1. A large ball was let go on a hill and started rolling down with a constant acceleration of 4.2 m/s². What was the velocity of the ball after 12 s?​

Answer 1

The velocity after 12s is 50.4m/s.

Step-by-step explanation:

In acceleration formula make velocity the subject.

acceleration(a) = velocity(v)÷time(t)

velocity (v) = acceleration(a)×time(t)

V = 4.2m/s²×12s

V = 50.4m/s

Therefore the velocity after 12s is 50.4m/s.