Question

Which of the following equations has both 2 and -4 as solutions

A x2 + 6x + 8 = 0
B x2 - 2x - 8= 0
C x2 + 2x - 8 = 0
D x2 - 2x + 8 = 0

Answer 1

c

Explanation:

Answer 2

Problem A; has -2 and -4 as solutions, so this is incorrect.

Problem B; has 4 and -2 as solutions; so this is incorrect.

Problem D; has 1 + √7i and 1 - √7i as solutions, this is also incorrect

Which leaves us to problem C;

Problem C;

Factor x^2 + 2x - 8

(x - 2)(x + 4) = 0

Solve for x

x = 2, -4

Your answer is C. x2 + 2x - 8 = 0