Question

Please help with math :)

Answer 1

Choice B is correct answer.

Explanation:

From given data,we observe that

a₁ = 3 and a₂ = 10 and a₃ = 17

Then the difference d between the successive terms is 7.

d = 7 which is constant.

Therefore, it is arithematic progression.

The formula for nth term of arithematic progression is :

f(n) = aₙ = a₁ + (n-1)d

putting above values in formula,we get

f(n) = 3+ (n-1)7

f(n) = 3+7n-7

f(n) = 7n-4 which is the answer.

Answer 2

ANSWER


`\boxed {f(n) = 7n - 4}`


EXPLANATION


From the table,


`a_1 = 3`



`a_2 = 10`




There is a constant difference of


`d = a_2 - a_1`



`d = 10 - 3 = 7`


The sequence is therefore an arithmetic progression.

The general formula for the arithmetic progression is


`f(n) = a_1 + (n - 1)d`

We substitute the values into the formula to obtain,


`f(n) = 3+ 7(n - 1)`



We expand the bracket to obtain,


`f(n) = 3+ 7n - 7`


This simplifies to


`f(n) =7n - 4`